Sequences (nth term)
Master sequences (nth term) for GCSE Maths with structured, exam-style practice. This Foundation and Higher resource covers finding the nth term of a linear sequence and includes a complete mark scheme showing the steps examiners reward. Suitable for AQA, Edexcel and OCR. Free to download as a PDF. For a linear sequence, the nth term is (common difference)n + (zero term).
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These worksheets and mark schemes are original, written for Virtus Academy and checked against the current AQA, Edexcel and OCR specifications. Every worksheet comes with a full mark scheme.
Topic overview
The nth term is a formula that gives any term of a sequence directly from its position, without listing the terms before it. It is also called the position-to-term rule.
For a linear sequence the formula is always \(dn + b\), where \(d\) is the common difference. The difference tells you the coefficient of \(n\) immediately, so \(4, 7, 10, 13\) starts as \(3n\).
The constant is then found by comparing \(3n\) with the actual sequence. The multiples of \(3\) are \(3, 6, 9, 12\), and each term of the sequence is one more, so the nth term is \(3n + 1\). Checking with a term you were given confirms it.
Revision notes
Finding the coefficient of n
The common difference becomes the number in front of \(n\).
For \(4, 7, 10, 13\) the difference is \(3\), so the formula begins \(3n\). A decreasing sequence gives a negative coefficient, so \(20, 17, 14\) begins \(-3n\).
Finding the constant
Write out the multiples of the difference and compare them with the sequence, term by term. The gap between them is the constant.
For \(4, 7, 10, 13\): the multiples of \(3\) are \(3, 6, 9, 12\), each one less than the sequence, so add \(1\), giving \(3n + 1\).
Using the nth term
Substitute a position to find that term, or set the formula equal to a value to test membership.
The \(50\)th term of \(3n + 1\) is \(151\). To check whether \(100\) is in the sequence, solve \(3n + 1 = 100\), giving \(n = 33\), a whole number, so yes.
Key points
- The nth term gives any term from its position.
- For a linear sequence it has the form \(dn + b\).
- The common difference is the coefficient of \(n\).
- Compare with multiples of the difference to find the constant.
- A decreasing sequence gives a negative coefficient.
- A whole-number solution means the value is in the sequence.
Worked examples
Example 1
Find the nth term of \(6, 11, 16, 21, \ldots\)
Working
Example 2
Find the nth term of \(19, 15, 11, 7, \ldots\)
Working
Example 3
Is \(83\) a term of the sequence \(4n + 3\)?
Working
Common mistakes
Using the first term as the constant.
For 4, 7, 10 the formula is 3n + 1, not 3n + 4. Compare with the multiples of 3.
Forgetting the negative for a decreasing sequence.
19, 15, 11 has difference −4, so the formula starts −4n.
Not checking the formula.
Substitute n = 1 and n = 2 to confirm it reproduces the sequence.
Concluding a value is in the sequence when n is not a whole number.
If solving gives n = 12.5, the value is not a term.
Exam tips
- Write the multiples of the difference under the sequence to find the constant.
- Always check your formula with two given terms.
- Use a negative coefficient for a decreasing sequence.
- For membership questions, solve and check whether n is a positive whole number.
Key terms
- nth term
- A formula giving any term from its position.
- Position-to-term rule
- Another name for the nth term formula.
- Coefficient
- The number multiplying n.
- Linear sequence
- A sequence with a constant difference.
Related topics
Written and reviewed against the current AQA, Edexcel and OCR specifications. Spotted an error? Let us know.